2x^2-8x+27=0

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Solution for 2x^2-8x+27=0 equation:



2x^2-8x+27=0
a = 2; b = -8; c = +27;
Δ = b2-4ac
Δ = -82-4·2·27
Δ = -152
Delta is less than zero, so there is no solution for the equation

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